Comments on Profile Post by Steve161803

prove it steve1611803

just type in google 1+1=3 proof, there is so many proofs, and each proof is different from the other

can you show me your favorite one

1 = 1

41 – 40 = 61 – 60

16 + 25 – 40 = 36 + 25 – 60

4² + 5² – 2 * 4 * 5 = 6² + 5² – 2 * 6 * 5

(4 – 5)² = (6 – 5)²

4 – 5 = 6 – 5

4 = 6

2 = 3

1 + 1 = 3…proved

man you said sqrt(1) = -1 and sqrt(1) = 1 in the same equation

what do you think about this one
a=b
ab=b^2
ab−a^2=b^2−a^2
a(b−a)=(b+a)(b−a)
a=b+a
a+1=b+a+1
a+1=2a+1
now if a=1 then:
1+1=2+1
1+1=3

if b=a then (b-a) = 0, you cant div by 0

Let x=y. Then

x - y + y = y

x - y + y y
--------- = ---
x-y x-y

y y
1 + --- = ---
x-y x-y

1 = 0

Now we know that 1 = 1, so add the following three equations together:

1 = 0
1 = 1
1 = 1

On the right is 1+1, and on the left is 3 ones, and 3 ones make 3.

-Doctor Ken, The Geometry Forum

All credit goes to doctor Ken

i think im getting trolled big time

I'm pretty sure this works

wait i dont really understand it
x - y + y = y
x - y + y = y
x-y = x-y
y = y
1 + --- = --- ??
x-y x-y

1 = 0

could you rewrite it

Let x=y. Then

x - y + y = y

x - y + y y
--------- = ---
x-y x-y

y y
1 + --- = ---
x-y x-y

1 = 0

Now we know that 1 = 1, so add the following three equations together:

1 = 0
1 = 1
1 = 1

On the right is 1+1, and on the left is 3 ones, and 3 ones make 3.

-Doctor Ken, The Geometry Forum

All credit goes to doctor Ken

it wont let me

Let x=y. Then

x - y + y = y

x - y + y y
--------- = ---
x-y x-y

y y
1 + --- = ---
x-y x-y

1 = 0

Now we know that 1 = 1, so add the following three equations together:

1 = 0
1 = 1
1 = 1

On the right is 1+1, and on the left is 3 ones, and 3 ones make 3.

-Doctor Ken, The Geometry Forum

All credit goes to doctor Ken

could you explain what the ---- = ---- and the variables above and below it mean

y
__
x-y

y
__
x-y

fractions, so 1 + y over x-y = y over x-y

if x=y then x-y = 0 yes? you cant have a fraction with 0 as the denominator

True

a=ba=b
(step 1) Multiply both sides by bb:
ab=b2ab=b2
(step 2) Subtract a2a2 from both sides and factorize:
ab−a2=b2−a2ab−a2=b2−a2
(step 3)
a(b−a)=(b+a)(b−a)a(b−a)=(b+a)(b−a)
(step 4) Simplify and add 1 to both sides:
a=b+a
(step 5)
a+1=b+a+1a+1=b+a+1
Now since a=ba=b (the starting point of this proof), we can write this as:
a+1=2a+1a+1=2a+1
And in the case where a=1a=1, we have:
1+1=2+11+1=2+1
So, therefore,
1+1=3

if a=1 and b=1 then you cant divide by (b-a) because its 0

Like all magic tricks, all you have to do is write a lot and hope the other person can't spot the mistake.