Selling Circles Are Added To Wynncraft!

2 le and 32 eb :3

 

someone bidded 3LE if you are not aware :3

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If the colliding objects are in the air, even if their initial motion is perpendicular to gravity, we cannot just take the final collision velocity as the one I calculated because the objects will still accelerate by g ''downward''. Of course, the horizontal component is unaffected.

However, if your reference frame is accelerating by g to where gravity points at, then even with gravity pointing at any direction, the V I calculated still works but it will be the V viewed from this accelerating reference frame. (Correct me if I am wrong)

EDIT: this reference frame thing only works if the objects are not placed on a table where no vertical net force acts on both of them

EDIT v2: Ding, just pretend there is no gravity la, if there is, then the whole process of bumping will be pulling the thread out from the pile of threads above and below it. That is applying a force larger than or equal to u times the total weight of all the threads including this thread horizontally. Then do work on the thread and increase its PE and then lift the Section Info thread and the thread above it and place this thread on top of all other threads. Lastly, Put back the Section Info thread and whatever the other one is called.

EDIT v3: Just go and revise for your DSE lol, I am here because I have free time (DSE next year)

 

ks F=(mv-mu)/t gravity doesn't matter in momentum change anyways but nvm you're just bumping the thread even if you're wrong it won't matter anyways coz u hv DSE next year but if you're wrong and I can't see it then I'm screwed tmr lol

 

4 le BADUM

 

I guess you won~

 

Im just bumping the thread, if you really have to put gravity into calculation, I guess you will have a very hard time if you do not consider an accelerating reference frame. You are not given the t (time of collision) , not given the average force acting on this thread by the metal ball (R), so how can you use the (Fnet)t=mv-mu equation to find V? In this case, this equation involves 5 variables, 1) u, 2) v, 3)m, 4)t and 5)R. Given only u and m, how can you find v without t and R?

And if gravity plays such a great role, I can't really 'bump' this thread for a substantial amount of time unless the V is really large.

Maybe when I first said 'I cant do momentum conservation when gravity is taken into account' , it made you think that I had a wrong concept. What I should have said was 'I cant do momentum conservation with the limited information given in a simple way when gravity is taken into account' because the collision happens in the mid-air, and t and R are not given.

Even so, I think this question is solvable

EDIT: Actually, let's just settle this question aside and leave it